\( B = 7 X + 15 ^ { \circ } < A = 3 X + 75 ^ { \circ } \)

To solve the inequality \( B = 7X + 15^\circ < A = 3X + 75^\circ \), we can start by substituting the expressions for \( A \) and \( B \) into the inequality: \[ 7X + 15^\circ < 3X + 75^\circ \] Next, we will isolate \( X \) by first subtracting \( 3X \) from both sides: \[ 7X - 3X + 15^\circ < 75^\circ \] This simplifies to: \[ 4X + 15^\circ < 75^\circ \] Now, we will subtract \( 15^\circ \) from both sides: \[ 4X < 75^\circ - 15^\circ \] This simplifies to: \[ 4X < 60^\circ \] Next, we divide both sides by 4: \[ X < \frac{60^\circ}{4} \] This simplifies to: \[ X < 15^\circ \] Thus, the solution to the inequality is: \[ X < 15^\circ \]