Find the area under the given curve over the indicated interval. $$ y=e^{2 x} ;[0,5] $$ The area is $$ \square $$. (Round to three decimal places as needed.)

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The area is approximately 11012.733 square units. Calculate the integral $$ \int_{0}^{5} e^{2x} dx $$. Evaluate the integral by following steps: - step0: Evaluate using formulas and rules: $$\int_{0}^{5} e^{2x} dx$$ - step1: Evaluate the integral: $$\int e^{2x} dx$$ - step2: Evaluate the integral: $$\frac{1}{2}e^{2x}$$ - step3: Return the limits: $$\left(\frac{1}{2}e^{2x}\right)\bigg |_{0}^{5}$$ - step4: Calculate the value: $$\frac{e^{10}-1}{2}$$ The area under the curve $$y=e^{2x}$$ over the interval $$[0,5]$$ is approximately 11012.733 square units.

Find the area under the given curve over the indicated interval. \( y=e^{2 x} ;[0,5] \) The area is \( \square \). (Round to three decimal places as needed.)

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Find the area under the given curve over the indicated interval. \( y=e^{2 x} ;[0,5] \) The area is \( \square \). (Round to three decimal places as needed.)

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