Horton Burgess
07/18/2024 · Junior High School

questions you held earller. Please submit an answer or pass. equation of a line that goes through the point \( (0,-5) \) and has a slope of \( -3 ? \)

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To find the equation of a line that goes through the point \( (0, -5) \) with a slope of \( -3 \), we can use the point-slope form of the equation of a line, which is given by: \[ y - y_1 = m(x - x_1) \] where \( (x_1, y_1) \) is a point on the line and \( m \) is the slope. In this case, the point is \( (0, -5) \) (so \( x_1 = 0 \) and \( y_1 = -5 \)), and the slope \( m = -3 \). Plugging these values into the point-slope form gives: \[ y - (-5) = -3(x - 0) \] This simplifies to: \[ y + 5 = -3x \] Now, we can isolate \( y \) to put the equation in slope-intercept form \( y = mx + b \): \[ y = -3x - 5 \] Thus, the equation of the line is: \[ y = -3x - 5 \]

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The equation of the line is \( y = -3x - 5 \).
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