Nunez Dickson
05/04/2024 · Middle School
2. Economics A cost function relates the total cost \( (C) \) of production to the number of items \( (x) \) produced per day. Acme Industries has a cost function \( C_{1}=300 x+ \) 500 , while Amalgamated Widgets' cost function is \( C_{2}=420 x+250 \). Using these facts, find a counterexample to this conjecture. For any value of \( x \), Acme Industries has lower costs than Amalgamated Widgets.
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To determine whether the conjecture "For any value of \( x \), Acme Industries has lower costs than Amalgamated Widgets" is true, we need to compare the cost functions of both companies for various values of \( x \).
The cost functions are given as follows:
- Acme Industries: \( C_1 = 300x + 500 \)
- Amalgamated Widgets: \( C_2 = 420x + 250 \)
To find a counterexample, we can set up the inequality:
\[
C_1 < C_2
\]
Substituting the cost functions into the inequality gives:
\[
300x + 500 < 420x + 250
\]
Now, we can simplify this inequality:
1. Subtract \( 300x \) from both sides:
\[
500 < 120x + 250
\]
2. Subtract \( 250 \) from both sides:
\[
250 < 120x
\]
3. Divide both sides by \( 120 \):
\[
\frac{250}{120} < x
\]
4. Simplifying \( \frac{250}{120} \):
\[
\frac{250}{120} = \frac{25}{12} \approx 2.0833
\]
This means that for any \( x \) greater than \( \frac{25}{12} \) (approximately 2.0833), Acme Industries does not have lower costs than Amalgamated Widgets.
### Counterexample
Let's choose \( x = 3 \) (which is greater than \( \frac{25}{12} \)):
- Calculate \( C_1 \) for \( x = 3 \):
\[
C_1 = 300(3) + 500 = 900 + 500 = 1400
\]
- Calculate \( C_2 \) for \( x = 3 \):
\[
C_2 = 420(3) + 250 = 1260 + 250 = 1510
\]
In this case, we find:
- \( C_1 = 1400 \)
- \( C_2 = 1510 \)
Thus, for \( x = 3 \), Acme Industries has lower costs than Amalgamated Widgets.
Now, let's try \( x = 4 \):
- Calculate \( C_1 \) for \( x = 4 \):
\[
C_1 = 300(4) + 500 = 1200 + 500 = 1700
\]
- Calculate \( C_2 \) for \( x = 4 \):
\[
C_2 = 420(4) + 250 = 1680 + 250 = 1930
\]
Again, we find:
- \( C_1 = 1700 \)
- \( C_2 = 1930 \)
Now, let's try \( x = 5 \):
- Calculate \( C_1 \) for \( x = 5 \):
\[
C_1 = 300(5) + 500 = 1500 + 500 = 2000
\]
- Calculate \( C_2 \) for \( x = 5 \):
\[
C_2 = 420(5) + 250 = 2100 + 250 = 2350
\]
Again, we find:
- \( C_1 = 2000 \)
- \( C_2 = 2350 \)
### Conclusion
To find a counterexample, we need to find a value of \( x \) such that \( C_1 \geq C_2 \).
Let's try \( x = 2 \):
- Calculate \( C_1 \) for \( x = 2 \):
\[
C_1 = 300(2) + 500 = 600 + 500 = 1100
\]
- Calculate \( C_2 \) for \( x = 2 \):
\[
C_2 = 420(2) + 250 = 840 + 250 = 1090
\]
In this case, we find:
- \( C_1 = 1100 \)
- \( C_2 = 1090 \)
Thus, for \( x = 2 \), Acme Industries has higher costs than Amalgamated Widgets, which serves as a counterexample to the conjecture.
Therefore, the conjecture is false.
Quick Answer
The conjecture is false. A counterexample is when \( x = 2 \), where Acme Industries has higher costs than Amalgamated Widgets.
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