UpStudy Free Solution:
To find the slope of the curve \(y^ 5 + x^ 3 = y^ 2 + 12x\) at the point \(( 0, 1) \), we need to find the derivative of \(y\) with respect to \(x\) using implicit differentiation.
Given:
\[y^ 5 + x^ 3 = y^ 2 + 12x\]
Differentiate both sides with respect to \(x\):
\[\frac { d} { dx} ( y^ 5) + \frac { d} { dx} ( x^ 3) = \frac { d} { dx} ( y^ 2) + \frac { d} { dx} ( 12x) \]
Using the chain rule, we get:
\[5y^ 4 \frac { dy} { dx} + 3x^ 2 = 2y \frac { dy} { dx} + 12\]
Rearrange the terms to solve for \(\frac { dy} { dx} \):
\[5y^ 4 \frac { dy} { dx} - 2y \frac { dy} { dx} = 12 - 3x^ 2\]
Factor out \(\frac { dy} { dx} \):
\[( 5y^ 4 - 2y) \frac { dy} { dx} = 12 - 3x^ 2\]
Solve for \(\frac { dy} { dx} \):
\[\frac { dy} { dx} = \frac { 12 - 3x^ 2} { 5y^ 4 - 2y} \]
Now, substitute the point \(( 0, 1) \) into the equation:
\[\frac { dy} { dx} \bigg | _ { ( 0, 1) } = \frac { 12 - 3( 0) ^ 2} { 5( 1) ^ 4 - 2( 1) } = \frac { 12 - 0} { 5 - 2} = \frac { 12} { 3} = 4\]
So, the slope of the curve at the point \(( 0, 1) \) is \(4\).
Therefore, the correct answer is:
b. 4
Supplemental Knowledge
When dealing with curves defined implicitly by an equation involving both \(x\) and \(y\), we use implicit differentiation to find the derivative. This allows us to determine the slope of the tangent line at a given point.
Implicit differentiation involves differentiating both sides of the equation with respect to \(x\), treating \(y\) as a function of \(x\). This means applying the chain rule to terms involving \(y\).
For an equation \(F( x, y) = 0\), we differentiate both sides:
\[\frac { d} { dx} F( x, y) = 0\]
This often results in an expression involving both \(x\), \(y\), and \(\frac { dy} { dx} \). We then solve for \(\frac { dy} { dx} \) to find the slope of the curve at a specific point.
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