Morgan Burgess
01/17/2023 · Senior High School
Calcule a energia livre de Gibbs padrão, \( \Delta_{\mathrm{r}} \mathrm{G}^{0} \), da reação: \( \mathrm{CO}_{(\mathrm{g})}+1 / 2 \mathrm{O}_{2(g)} \rightarrow \mathrm{CO}_{2(g)} \) à \( 25^{\circ} \mathrm{C} \) Dados: \( \Delta, G^{\circ}: \mathrm{CO}_{2(g)}=-394,4 \mathrm{~kJ} \mathrm{~mol}^{-1}, \mathrm{CO}_{(g)}=-137,2 \mathrm{~kJ} \mathrm{~mol}^{-1} \)
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Para calcular a energia livre de Gibbs padrão, \( \Delta_{\mathrm{r}} \mathrm{G}^{0} \), da reação fornecida, precisamos usar a fórmula:
\[ \Delta_{\mathrm{r}} \mathrm{G}^{0} = \sum \Delta \mathrm{G}^{0}_{\mathrm{produtos}} - \sum \Delta \mathrm{G}^{0}_{\mathrm{reagentes}} \]
Dada a reação:
\[ \mathrm{CO}_{(\mathrm{g})} + \frac{1}{2} \mathrm{O}_{2(g)} \rightarrow \mathrm{CO}_{2(g)} \]
E os valores de \( \Delta \mathrm{G}^{0} \) para os produtos e reagentes:
- \( \Delta \mathrm{G}^{0} \) para \(\mathrm{CO}_{2(g)} = -394,4 \, \mathrm{kJ} \, \mathrm{mol}^{-1}\)
- \( \Delta \mathrm{G}^{0} \) para \(\mathrm{CO}_{(g)} = -137,2 \, \mathrm{kJ} \, \mathrm{mol}^{-1}\)
Vamos calcular a energia livre de Gibbs padrão da reação.
Calculate the value by following steps:
- step0: Calculate:
\(-394.4+137.2\)
- step1: Add the numbers:
\(-257.2\)
A energia livre de Gibbs padrão, \( \Delta_{\mathrm{r}} \mathrm{G}^{0} \), da reação fornecida é de -257.2 kJ/mol.
Quick Answer
A energia livre de Gibbs padrão da reação é de -257.2 kJ/mol.
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