Weaver Mckenzie
05/18/2023 · Elementary School

unbalanced equations for two redox reactions, in which \( \mathrm{SO}_{2} \) is involved, are wn below. action 1: \( \mathrm{SO}_{2}(\mathrm{~g})+\mathrm{H}_{2} \mathrm{~S}(\mathrm{~g}) \rightarrow \mathrm{S}(\mathrm{s})+\mathrm{H}_{2} \mathrm{O}(\ell) \) Explain what is meant by the term redox reaction. \( \mathrm{SO}_{2}(\mathrm{~g})+\mathrm{KMnO}_{4}(\mathrm{~s})+\mathrm{H}_{2} \mathrm{O}(\ell) \rightarrow \mathrm{MnSO}_{4}(\mathrm{aq})+\mathrm{K}_{2} \mathrm{SO}_{4}(\mathrm{aq})+\mathrm{H}_{2} \mathrm{SO}_{4}(\mathrm{aq}) \) Write down the oxidation number of Mn in: 9.2.1 \( \quad \mathrm{KMnO}_{4} \) 9.2.2 \( \quad \mathrm{MnSO}_{4} \) Is Mn in Reaction 2 OXIDISED or REDUCED? Give a reason for the answer. In which reaction, Reaction 1 or Reaction 2, does \( \mathrm{SO}_{2} \) act as an oxidising agent? Give a reason for the answer. Write down the oxidation half-reaction in Reaction 1. Use the Table of Standard Reduction Potentials and write down the balanced net ionic equation for Reaction 1 . Show the half-reactions and how you arrived at the final equation.

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A redox reaction involves the transfer of electrons between species, with one species being oxidized and the other reduced. In \( \mathrm{KMnO}_{4} \), Mn has an oxidation number of +7, and in \( \mathrm{MnSO}_{4} \), it is +2. Mn is reduced in Reaction 2. \( \mathrm{SO}_{2} \) is not the oxidizing agent in either reaction. The oxidation half-reaction in Reaction 1 is \( \mathrm{H}_{2}\mathrm{S} \rightarrow \mathrm{S} + 2\mathrm{H}^{+} + 2e^{-} \). The balanced net ionic equation for Reaction 1 is \( \mathrm{SO}_{2} + \mathrm{H}_{2}\mathrm{S} \rightarrow \mathrm{S} + \mathrm{H}_{2}\mathrm{O} \).

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