$$ A=L^{2}=28.09 \mathrm{~m}^{2} $$ $$ \mathrm{~L}=5.3 \mathrm{~m} $$ Perimetro $$ =4(5.3 \mathrm{~m})=21.2 \mathrm{~m} $$

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The area is $$ 28.09 \, \text{m}^2 $$, the side length is $$ 5.3 \, \text{m} $$, and the perimeter is $$ 21.2 \, \text{m} $$. It looks like you're working with a square or rectangular area and its perimeter. Let's clarify the calculations based on the information provided. 1. **Area Calculation**: You mentioned that $$ A = L^2 = 28.09 \, \text{m}^2 $$. This implies that the shape is a square, and the side length $$ L $$ should be calculated as follows: $$ L = \sqrt{A} = \sqrt{28.09 \, \text{m}^2} \approx 5.3 \, \text{m} $$ This matches the value you provided for $$ L $$. 2. **Perimeter Calculation**: The perimeter $$ P $$ of a square is calculated using the formula: $$ P = 4L $$ Substituting the value of $$ L $$: $$ P = 4(5.3 \, \text{m}) = 21.2 \, \text{m} $$ This calculation is also correct. In summary, you have correctly calculated the area, side length, and perimeter of the square. If you have any further questions or need additional calculations, feel free to ask!

\( A=L^{2}=28.09 \mathrm{~m}^{2} \) \( \mathrm{~L}=5.3 \mathrm{~m} \) Perimetro \( =4(5.3 \mathrm{~m})=21.2 \mathrm{~m} \)

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\( A=L^{2}=28.09 \mathrm{~m}^{2} \) \( \mathrm{~L}=5.3 \mathrm{~m} \) Perimetro \( =4(5.3 \mathrm{~m})=21.2 \mathrm{~m} \)

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