\( \left. \begin{array} { l } { \theta ^ { 2 } = 1 ^ { 2 } \quad ( 6 = 1 ) ^ { 2 } } \\ { \theta ^ { 2 } = 1 ^ { 2 } = 95 } \\ { ( 0 - 1 ) ^ { 2 } = \square } \end{array} \right. \)

Let's analyze the equations provided step by step. 1. The first equation is \( \theta^2 = 1^2 \). This simplifies to \( \theta^2 = 1 \). Therefore, \( \theta = 1 \) or \( \theta = -1 \). 2. The second equation is \( (6 = 1)^2 \). This expression is not mathematically valid as it stands, since \( 6 \neq 1 \). However, if we interpret it as \( (6 - 1)^2 \), we get \( 5^2 = 25 \). 3. The next equation states \( \theta^2 = 1^2 = 95 \). This is also incorrect because \( 1^2 = 1 \), not 95. Therefore, this equation does not hold true. 4. The last equation is \( (0 - 1)^2 = \square \). This simplifies to \( (-1)^2 = 1 \). Thus, \( \square = 1 \). In summary, the valid conclusions we can draw from the equations are: - \( \theta^2 = 1 \) implies \( \theta = 1 \) or \( \theta = -1 \). - The expression \( (0 - 1)^2 \) evaluates to \( 1 \). If you have any specific questions or need further clarification, feel free to ask!