Write an equation in slope-intercept form of the line that passes through the given point and is \( p \) \( (-3,-3) ; y=-5 x+1 \) Write an equation for the line in slope-intercept form. \( \square \) (Simplify \( \ \) our answer. Use integers or fractions for any numbers in the equation.)

To find the equation of the line that passes through the point \((-3, -3)\) and is parallel to the line given by the equation \(y = -5x + 1\), we first note that parallel lines have the same slope. The slope of the given line \(y = -5x + 1\) is \(-5\). Therefore, the slope of the line we want to find is also \(-5\). We can use the point-slope form of the equation of a line, which is given by: \[ y - y_1 = m(x - x_1) \] where \((x_1, y_1)\) is the point the line passes through and \(m\) is the slope. Here, \((x_1, y_1) = (-3, -3)\) and \(m = -5\). Substituting these values into the point-slope form: \[ y - (-3) = -5(x - (-3)) \] This simplifies to: \[ y + 3 = -5(x + 3) \] Now, distribute \(-5\): \[ y + 3 = -5x - 15 \] Next, isolate \(y\) by subtracting \(3\) from both sides: \[ y = -5x - 15 - 3 \] This simplifies to: \[ y = -5x - 18 \] Thus, the equation of the line in slope-intercept form is: \[ \boxed{y = -5x - 18} \]