\( 2^{3} \times 3 \times 2 \times 3^{6}= \) A \( 2^{3} \times 3^{6} \) B \( 2^{4} \times 3^{7} \) C \( 6^{28} \) D \( 6^{11} \)

To simplify the expression \( 2^{3} \times 3 \times 2 \times 3^{6} \), we can first rearrange and group the terms: \[ 2^{3} \times 2 \times 3 \times 3^{6} \] Now, we can combine the powers of 2 and the powers of 3: 1. For the base 2: \[ 2^{3} \times 2 = 2^{3+1} = 2^{4} \] 2. For the base 3: \[ 3 \times 3^{6} = 3^{1+6} = 3^{7} \] Now we can combine these results: \[ 2^{4} \times 3^{7} \] Thus, the expression simplifies to: \[ 2^{4} \times 3^{7} \] Now, let's compare this with the options provided: A) \( 2^{3} \times 3^{6} \) B) \( 2^{4} \times 3^{7} \) C) \( 6^{28} \) D) \( 6^{11} \) The correct answer is: \[ \boxed{B} \]