West Wang
01/04/2024 · Middle School
Reduce a una sola potencia de base positiva \( \begin{array}{ll}\text { a) }\left((-5)^{3}\right)^{3} & \text { d) }\left((-2)^{2}\right)^{5} \\ \text { b) }\left((-3)^{8}\right)^{2} & \text { e) }\left((-3)^{3}\right)^{7} \\ \text { c) }\left((-9)^{3}\right)^{8} & \text { f) }\left((-8)^{6}\right)^{4}\end{array} \)
UpStudy ThothAI Solution
Tutor-Verified Answer
Step-by-step Solution
Para reducir cada expresión a una sola potencia de base positiva, utilizaremos la regla de la potencia de una potencia, que dice que \((a^m)^n = a^{m \cdot n}\). Aquí vamos con cada una de las expresiones:
a) \(\left((-5)^{3}\right)^{3}\)
\[
\begin{align*}
\left((-5)^{3}\right)^{3} &= (-5)^{3 \cdot 3} \\
&= (-5)^{9}
\end{align*}
\]
b) \(\left((-3)^{8}\right)^{2}\)
\[
\begin{align*}
\left((-3)^{8}\right)^{2} &= (-3)^{8 \cdot 2} \\
&= (-3)^{16}
\end{align*}
\]
c) \(\left((-9)^{3}\right)^{8}\)
\[
\begin{align*}
\left((-9)^{3}\right)^{8} &= (-9)^{3 \cdot 8} \\
&= (-9)^{24}
\end{align*}
\]
d) \(\left((-2)^{2}\right)^{5}\)
\[
\begin{align*}
\left((-2)^{2}\right)^{5} &= (-2)^{2 \cdot 5} \\
&= (-2)^{10}
\end{align*}
\]
e) \(\left((-3)^{3}\right)^{7}\)
\[
\begin{align*}
\left((-3)^{3}\right)^{7} &= (-3)^{3 \cdot 7} \\
&= (-3)^{21}
\end{align*}
\]
f) \(\left((-8)^{6}\right)^{4}\)
\[
\begin{align*}
\left((-8)^{6}\right)^{4} &= (-8)^{6 \cdot 4} \\
&= (-8)^{24}
\end{align*}
\]
En cada caso, hemos reducido la expresión a una sola potencia de base positiva utilizando la regla de la potencia de una potencia.
Quick Answer
a) \((-5)^{9}\)
b) \((-3)^{16}\)
c) \((-9)^{24}\)
d) \((-2)^{10}\)
e) \((-3)^{21}\)
f) \((-8)^{24}\)
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