Simpson Ellis
01/27/2023 · Senior High School
Tomando los vectores a, \( \boldsymbol{b} \) y \( c \) definidos como: \( a=\{3,1,6\rangle, b=\langle-1,2,3\rangle \) y \( c=2 t+5 j-2 k \) determine el grado de verdad de la expresión (1) \[ a \text {. }(b \times c)=\boldsymbol{a} \times \boldsymbol{b}+\boldsymbol{a} . \boldsymbol{c} \]
UpStudy ThothAI Solution
Tutor-Verified Answer
Step-by-step Solution
Para determinar el grado de verdad de la expresión dada, primero necesitamos calcular los productos vectoriales y el producto escalar de los vectores involucrados.
Dado que los vectores \( \boldsymbol{a} \), \( \boldsymbol{b} \) y \( \boldsymbol{c} \) se definen de la siguiente manera:
- \( \boldsymbol{a} = \langle 3, 1, 6 \rangle \)
- \( \boldsymbol{b} = \langle -1, 2, 3 \rangle \)
- \( \boldsymbol{c} = 2t + 5j - 2k \)
Calculamos los productos vectoriales y el producto escalar de los vectores involucrados:
1. \( \boldsymbol{b} \times \boldsymbol{c} \):
\[ \boldsymbol{b} \times \boldsymbol{c} = \begin{vmatrix} \boldsymbol{i} & \boldsymbol{j} & \boldsymbol{k} \\ -1 & 2 & 3 \\ 2t & 5 & -2 \end{vmatrix} \]
\[ \boldsymbol{b} \times \boldsymbol{c} = \boldsymbol{i}(-2 - 10t) - \boldsymbol{j}(-2 - 6t) + \boldsymbol{k}(2 + 2t) \]
\[ \boldsymbol{b} \times \boldsymbol{c} = \langle -2 - 10t, 2 + 6t, 2 + 2t \rangle \]
2. \( \boldsymbol{a} \times \boldsymbol{b} \):
\[ \boldsymbol{a} \times \boldsymbol{b} = \begin{vmatrix} \boldsymbol{i} & \boldsymbol{j} & \boldsymbol{k} \\ 3 & 1 & 6 \\ -1 & 2 & 3 \end{vmatrix} \]
\[ \boldsymbol{a} \times \boldsymbol{b} = \boldsymbol{i}(3 - 12) - \boldsymbol{j}(18 - 6) + \boldsymbol{k}(6 + 3) \]
\[ \boldsymbol{a} \times \boldsymbol{b} = \langle -9, 12, 9 \rangle \]
3. \( \boldsymbol{a} \cdot \boldsymbol{c} \):
\[ \boldsymbol{a} \cdot \boldsymbol{c} = (3)(2t) + (1)(5) + (6)(-2) \]
\[ \boldsymbol{a} \cdot \boldsymbol{c} = 6t + 5 - 12 \]
\[ \boldsymbol{a} \cdot \boldsymbol{c} = 6t - 7 \]
Ahora, evaluamos la expresión dada:
\[ \boldsymbol{a} \cdot (\boldsymbol{b} \times \boldsymbol{c}) = \boldsymbol{a} \cdot \langle -2 - 10t, 2 + 6t, 2 + 2t \rangle \]
\[ \boldsymbol{a} \cdot (\boldsymbol{b} \times \boldsymbol{c}) = (3)(-2 - 10t) + (1)(2 + 6t) + (6)(2 + 2t) \]
\[ \boldsymbol{a} \cdot (\boldsymbol{b} \times \boldsymbol{c}) = -6 - 30t + 2 + 6t + 12 + 12t \]
\[ \boldsymbol{a} \cdot (\boldsymbol{b} \times \boldsymbol{c}) = -6 + 2 + 12 - 30t + 6t + 12t \]
\[ \boldsymbol{a} \cdot (\boldsymbol{b} \times \boldsymbol{c}) = 8 - 12t \]
Por lo tanto, la expresión dada es verdadera si \( 8 - 12t = 6t - 7 \). Resolviendo esta ecuación, encontramos que la expresión es verdadera para todos los valores de \( t \).
Quick Answer
La expresión es verdadera para todos los valores de \( t \).
Answered by UpStudy AI and reviewed by a Professional Tutor
UpStudy ThothAI
Self-Developed and Ever-Improving
Thoth AI product is constantly being upgraded and optimized.
Covers All Major Subjects
Capable of handling homework in math, chemistry, biology, physics, and more.
Instant and Accurate
Provides immediate and precise solutions and guidance.
Try Now
Ask Tutors
Ask AI
10x
Fastest way to Get Answers & Solutions
By text
Enter your question here…
By image
Re-Upload
Submit