Reed Ellis
01/19/2024 · Senior High School
Soit \( \left(w_{n}\right) \) la suite définie pour tout \( n \in \mathbb{N} \) par \[ w_{n}=n^{2}+2 n+(-1)^{n} n \] 1. Justifier que \( w_{n} \geqslant n^{2} \), pour tout \( n \in \mathbb{N} \). 2. En déduire la limite de la suite \( \left(w_{n}\right) \)
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1. Pour justifier que \( w_{n} \geqslant n^{2} \) pour tout \( n \in \mathbb{N} \), on factorise \( w_{n} \) et considère les cas de \( n \) pair et impair. Dans les deux cas, \( w_{n} \) est supérieur ou égal à \( n^{2} \).
2. La limite de la suite \( (w_{n}) \) est \( \infty \) car \( w_{n} \) tend vers l'infini lorsque \( n \) tend vers l'infini.
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