\( \left. \begin{array} { l } { Mg + HCl \rightarrow MgCl _ { 2 } + H _ { 2 } } \end{array} \right. \)

The reaction you've provided is a chemical equation representing the reaction between magnesium (Mg) and hydrochloric acid (HCl). The products of this reaction are magnesium chloride (MgCl₂) and hydrogen gas (H₂). To balance the equation, we need to ensure that the number of atoms of each element is the same on both sides of the equation. The unbalanced equation is: \[ \text{Mg} + \text{HCl} \rightarrow \text{MgCl}_2 + \text{H}_2 \] To balance it, we can follow these steps: 1. **Count the atoms on each side**: - Reactants: 1 Mg, 1 Cl (from HCl), 1 H (from HCl) - Products: 1 Mg, 2 Cl (from MgCl₂), 2 H (from H₂) 2. **Balance the chlorine and hydrogen**: - Since there are 2 Cl in the products, we need 2 HCl in the reactants to provide 2 Cl and 2 H. The balanced equation becomes: \[ \text{Mg} + 2 \text{HCl} \rightarrow \text{MgCl}_2 + \text{H}_2 \] Now, both sides have: - 1 Mg - 2 Cl - 2 H This equation is now balanced.