Vargas Carrillo
07/25/2024 · Junior High School
Find the rate at which the surface area of the ball is increasing when the radius of the ball is 20 cm .
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The rate of change of the surface area of the ball with respect to time is \( 160\pi \cdot \frac{dr}{dt} \) cm²/s, where \( \frac{dr}{dt} \) is the rate of change of the radius.
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