For each of the following statements, write down an equation and solve it. (a) Five more than \( x \) is equal to 11 . (b) If I take 3 from \( y \) the answer is 6 . (c) Three times \( m \) is equal to 18 . (d) If \( x \) is divided by 6 , the answer is 4 . (e) Four less than \( y \) is 6 . (f) Thula has 45 sweets. She divides them equally among \( q \) girls so that ear girl gets five sweets.

Let's write down the equations for each statement and solve them one by one. (a) Five more than \( x \) is equal to 11. \[ x + 5 = 11 \] To solve for \( x \), subtract 5 from both sides: \[ x = 11 - 5 \] \[ x = 6 \] (b) If I take 3 from \( y \), the answer is 6. \[ y - 3 = 6 \] To solve for \( y \), add 3 to both sides: \[ y = 6 + 3 \] \[ y = 9 \] (c) Three times \( m \) is equal to 18. \[ 3m = 18 \] To solve for \( m \), divide both sides by 3: \[ m = \frac{18}{3} \] \[ m = 6 \] (d) If \( x \) is divided by 6, the answer is 4. \[ \frac{x}{6} = 4 \] To solve for \( x \), multiply both sides by 6: \[ x = 4 \times 6 \] \[ x = 24 \] (e) Four less than \( y \) is 6. \[ y - 4 = 6 \] To solve for \( y \), add 4 to both sides: \[ y = 6 + 4 \] \[ y = 10 \] (f) Thula has 45 sweets. She divides them equally among \( q \) girls so that each girl gets five sweets. \[ \frac{45}{q} = 5 \] To solve for \( q \), multiply both sides by \( q \): \[ 45 = 5q \] Now, divide both sides by 5: \[ q = \frac{45}{5} \] \[ q = 9 \] Here are the solutions: (a) \( x = 6 \) (b) \( y = 9 \) (c) \( m = 6 \) (d) \( x = 24 \) (e) \( y = 10 \) (f) \( q = 9 \)