Romero Mann
03/23/2024 · Junior High School
\( \begin{array}{lll}\text { a) } \frac{1}{2} \square \frac{3}{4} & \text { b) } \frac{6}{5} \square-\frac{5}{6} & \text { c) }-\frac{2}{3} \square-\frac{3}{5} \\ \text { d) }-\frac{11}{18} \square \frac{12}{19} & \text { e) }-\frac{4}{6} \square-\frac{2}{3} & \text { f) } \frac{32}{51} \square \frac{41}{82}\end{array} \)
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Step-by-step Solution
To solve the problems, we need to determine the appropriate operation (addition, subtraction, multiplication, or division) to place in the squares. Let's analyze each case one by one.
### a) \( \frac{1}{2} \square \frac{3}{4} \)
1. **Addition**: \( \frac{1}{2} + \frac{3}{4} = \frac{2}{4} + \frac{3}{4} = \frac{5}{4} \)
2. **Subtraction**: \( \frac{1}{2} - \frac{3}{4} = \frac{2}{4} - \frac{3}{4} = -\frac{1}{4} \)
3. **Multiplication**: \( \frac{1}{2} \times \frac{3}{4} = \frac{3}{8} \)
4. **Division**: \( \frac{1}{2} \div \frac{3}{4} = \frac{1}{2} \times \frac{4}{3} = \frac{4}{6} = \frac{2}{3} \)
**Conclusion**: Any operation can be used, but if we want a specific operation, we can choose addition.
### b) \( \frac{6}{5} \square -\frac{5}{6} \)
1. **Addition**: \( \frac{6}{5} + -\frac{5}{6} = \frac{36}{30} - \frac{25}{30} = \frac{11}{30} \)
2. **Subtraction**: \( \frac{6}{5} - -\frac{5}{6} = \frac{6}{5} + \frac{5}{6} = \frac{36}{30} + \frac{25}{30} = \frac{61}{30} \)
3. **Multiplication**: \( \frac{6}{5} \times -\frac{5}{6} = -1 \)
4. **Division**: \( \frac{6}{5} \div -\frac{5}{6} = \frac{6}{5} \times -\frac{6}{5} = -\frac{36}{25} \)
**Conclusion**: The multiplication operation gives a simple result of \(-1\).
### c) \( -\frac{2}{3} \square -\frac{3}{5} \)
1. **Addition**: \( -\frac{2}{3} + -\frac{3}{5} = -\frac{10}{15} - \frac{9}{15} = -\frac{19}{15} \)
2. **Subtraction**: \( -\frac{2}{3} - -\frac{3}{5} = -\frac{2}{3} + \frac{3}{5} = -\frac{10}{15} + \frac{9}{15} = -\frac{1}{15} \)
3. **Multiplication**: \( -\frac{2}{3} \times -\frac{3}{5} = \frac{6}{15} = \frac{2}{5} \)
4. **Division**: \( -\frac{2}{3} \div -\frac{3}{5} = -\frac{2}{3} \times -\frac{5}{3} = \frac{10}{9} \)
**Conclusion**: The multiplication operation gives a positive result of \(\frac{2}{5}\).
### d) \( -\frac{11}{18} \square \frac{12}{19} \)
1. **Addition**: \( -\frac{11}{18} + \frac{12}{19} = -\frac{209}{342} + \frac{216}{342} = \frac{7}{342} \)
2. **Subtraction**: \( -\frac{11}{18} - \frac{12}{19} = -\frac{209}{342} - \frac{216}{342} = -\frac{425}{342} \)
3. **Multiplication**: \( -\frac{11}{18} \times \frac{12}{19} = -\frac{132}{342} = -\frac{22}{57} \)
4. **Division**: \( -\frac{11}{18} \div \frac{12}{19} = -\frac{11}{18} \times \frac{19}{12} = -\frac{209}{216} \)
**Conclusion**
Quick Answer
a) Any operation can be used, addition gives \( \frac{5}{4} \).
b) Multiplication gives \(-1\).
c) Multiplication gives \( \frac{2}{5} \).
d) Multiplication gives \(-\frac{22}{57} \).
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