Johnson Pollard
09/18/2024 · Primary School
5. Un alambre de 80 m de largo se va a partir en dos pedazos; una de las partes se dobla- rá para formar una circunferencia y la otra un triángulo equilátero. ¿Cómo se debe cortar el alambre para que la suma de las áreas del círculo y del triángulo sean máximas?
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Para maximizar la suma de áreas del triángulo equilátero y del círculo, corta el alambre en aproximadamente 49.85 m para el triángulo y 30.15 m para la circunferencia.
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