Pierce Rogers
08/18/2023 · Senior High School
orden de las fracciones \( a=5 \frac{2}{3}, b=5 \frac{5}{6} \) y \( c=5 \frac{7}{8} \), de menor a mayor es
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Para resolver este problema, primero convertiremos las fracciones mixtas en fracciones improperas. Luego, compararemos los numeradores de estas fracciones para determinar el orden correcto.
1. Convertir las fracciones mixtas a fracciones improperas:
- \( a = 5 \frac{2}{3} = 5 + \frac{2}{3} = \frac{5 \times 3 + 2}{3} = \frac{15 + 2}{3} = \frac{17}{3} \)
- \( b = 5 \frac{5}{6} = 5 + \frac{5}{6} = \frac{5 \times 6 + 5}{6} = \frac{30 + 5}{6} = \frac{35}{6} \)
- \( c = 5 \frac{7}{8} = 5 + \frac{7}{8} = \frac{5 \times 8 + 7}{8} = \frac{40 + 7}{8} = \frac{47}{8} \)
2. Comparar las fracciones improperas:
- \( \frac{17}{3} \), \( \frac{35}{6} \), \( \frac{47}{8} \)
Para compararlas, podemos encontrar un denominador común. El menor común múltiplo de 3, 6 y 8 es 24. Convertiremos cada fracción al denominador 24:
- \( \frac{17}{3} = \frac{17 \times 8}{3 \times 8} = \frac{136}{24} \)
- \( \frac{35}{6} = \frac{35 \times 4}{6 \times 4} = \frac{140}{24} \)
- \( \frac{47}{8} = \frac{47 \times 3}{8 \times 3} = \frac{141}{24} \)
Ahora, podemos comparar los numeradores:
- \( \frac{136}{24} \), \( \frac{140}{24} \), \( \frac{141}{24} \)
El orden de las fracciones de menor a mayor es:
- \( a = 5 \frac{2}{3} = \frac{17}{3} = \frac{136}{24} \)
- \( b = 5 \frac{5}{6} = \frac{35}{6} = \frac{140}{24} \)
- \( c = 5 \frac{7}{8} = \frac{47}{8} = \frac{141}{24} \)
Por lo tanto, el orden de las fracciones de menor a mayor es \( a, b, c \).
Quick Answer
El orden de las fracciones de menor a mayor es \( a, b, c \).
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