b. \( 89+(76-43) \) e. \( 78+4 \cdot(65-43) \) h. \( 3(56-76)-5(32+76) \) j. \( (76-456) \cdot 4+3(76+98 \) l. \( (67-32): 7-(98+65) \) n. \( 76-(65-43) \)

Let's solve each problem step by step following the order of operations (PEMDAS/BODMAS: Parentheses/Brackets, Exponents/Orders, Multiplication and Division (from left to right), and Addition and Subtraction (from left to right)). b. \( 89 + (76 - 43) \) 1. Solve the parentheses: \( 76 - 43 = 33 \) 2. Add the result to 89: \( 89 + 33 = 122 \) e. \( 78 + 4 \cdot (65 - 43) \) 1. Solve the parentheses: \( 65 - 43 = 22 \) 2. Multiply the result by 4: \( 4 \cdot 22 = 88 \) 3. Add the result to 78: \( 78 + 88 = 166 \) h. \( 3(56 - 76) - 5(32 + 76) \) 1. Solve the parentheses: \( 56 - 76 = -20 \) and \( 32 + 76 = 108 \) 2. Multiply the results by their respective numbers: \( 3 \cdot (-20) = -60 \) and \( 5 \cdot 108 = 540 \) 3. Subtract the second product from the first: \( -60 - 540 = -600 \) j. \( (76 - 456) \cdot 4 + 3(76 + 98) \) 1. Solve the parentheses: \( 76 - 456 = -380 \) and \( 76 + 98 = 174 \) 2. Multiply the results by their respective numbers: \( -380 \cdot 4 = -1520 \) and \( 3 \cdot 174 = 522 \) 3. Add the second product to the first: \( -1520 + 522 = -998 \) l. \( (67 - 32) : 7 - (98 + 65) \) 1. Solve the parentheses: \( 67 - 32 = 35 \) and \( 98 + 65 = 163 \) 2. Divide the first result by 7: \( 35 : 7 = 5 \) 3. Subtract the second result from the first: \( 5 - 163 = -158 \) n. \( 76 - (65 - 43) \) 1. Solve the parentheses: \( 65 - 43 = 22 \) 2. Subtract the result from 76: \( 76 - 22 = 54 \) So the solutions are: b. 122 e. 166 h. -600 j. -998 l. -158 n. 54