Lawson Harper
07/11/2023 · Senior High School
A runner burns \( 2.91 \times 10^{3} \mathrm{~kJ} \) during a five-mile run. How many nutritional Calories did the runner burn? 696 Cal \( 6.96 \times 10^{5} \mathrm{Cal} \) \( 1.22 \times 10^{4} \mathrm{Cal} \) \( 1.22 \times 10^{1} \mathrm{Cal} \) Submit Request Answer
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Tutor-Verified Answer
Step-by-step Solution
To convert kilojoules (kJ) to nutritional Calories (Cal), we can use the conversion factor:
\[
1 \text{ Cal} = 4.184 \text{ kJ}
\]
Given that the runner burns \( 2.91 \times 10^{3} \text{ kJ} \), we can convert this to Calories using the following formula:
\[
\text{Calories} = \frac{\text{kJ}}{4.184}
\]
Substituting the given value:
\[
\text{Calories} = \frac{2.91 \times 10^{3} \text{ kJ}}{4.184 \text{ kJ/Cal}} \approx 696.0 \text{ Cal}
\]
Thus, the runner burned approximately \( 696 \text{ Cal} \).
The correct answer is:
**696 Cal**
Quick Answer
The runner burned approximately 696 Calories.
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