Lawson Harper
07/11/2023 · Senior High School

A runner burns \( 2.91 \times 10^{3} \mathrm{~kJ} \) during a five-mile run. How many nutritional Calories did the runner burn? 696 Cal \( 6.96 \times 10^{5} \mathrm{Cal} \) \( 1.22 \times 10^{4} \mathrm{Cal} \) \( 1.22 \times 10^{1} \mathrm{Cal} \) Submit Request Answer

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To convert kilojoules (kJ) to nutritional Calories (Cal), we can use the conversion factor: \[ 1 \text{ Cal} = 4.184 \text{ kJ} \] Given that the runner burns \( 2.91 \times 10^{3} \text{ kJ} \), we can convert this to Calories using the following formula: \[ \text{Calories} = \frac{\text{kJ}}{4.184} \] Substituting the given value: \[ \text{Calories} = \frac{2.91 \times 10^{3} \text{ kJ}}{4.184 \text{ kJ/Cal}} \approx 696.0 \text{ Cal} \] Thus, the runner burned approximately \( 696 \text{ Cal} \). The correct answer is: **696 Cal**

Quick Answer

The runner burned approximately 696 Calories.
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