Vaughn Robbins
09/29/2024 · High School
A quadratic curve where the coefficient of \( x^{2} \) is 2 , has a line of symmetry \( x=4 \) and passes through the point \( (6,-2) \). Find the equation of the curve in the form of \( y=a x^{2}+b x+c \), where \( a, b \) and \( c \) are constants to be found.
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The equation of the curve is \( y = 2x^2 - 16x + 22 \).
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