Solve the formula for \( h \). \( V=6 \pi z h+4 \pi z^{2} \) constant terms on the left side?

To solve the formula \( V = 6 \pi z h + 4 \pi z^2 \) for \( h \), we can start by isolating the term that contains \( h \). 1. Subtract \( 4 \pi z^2 \) from both sides: \[ V - 4 \pi z^2 = 6 \pi z h \] 2. Now, divide both sides by \( 6 \pi z \) to solve for \( h \): \[ h = \frac{V - 4 \pi z^2}{6 \pi z} \] Thus, the solution for \( h \) is: \[ h = \frac{V - 4 \pi z^2}{6 \pi z} \] Regarding your question about constant terms on the left side, the left side of the equation \( V \) is treated as a constant with respect to \( h \), \( z \), and \( \pi \). The terms \( 6 \pi z h \) and \( 4 \pi z^2 \) are dependent on \( h \) and \( z \), while \( V \) is a constant value in this context.