Mccarthy O'Quinn
01/16/2023 · Elementary School
\( ( A \cup B ) \cap ( B \cup C ) \)
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Tutor-Verified Answer
Step-by-step Solution
To simplify the expression \( ( A \cup B ) \cap ( B \cup C ) \), we can use the properties of set operations.
1. **Distributive Law**: The intersection distributes over the union. We can rewrite the expression as follows:
\[
( A \cup B ) \cap ( B \cup C ) = ( A \cap ( B \cup C )) \cup ( B \cap ( B \cup C ))
\]
2. **Simplifying \( B \cap ( B \cup C ) \)**: Since \( B \) is a subset of \( B \cup C \), we have:
\[
B \cap ( B \cup C ) = B
\]
3. **Now substituting back**: We can substitute this back into our expression:
\[
( A \cup B ) \cap ( B \cup C ) = A \cap ( B \cup C ) \cup B
\]
4. **Final Expression**: The final simplified expression is:
\[
( A \cup B ) \cap ( B \cup C ) = ( A \cap ( B \cup C )) \cup B
\]
This means that the result of the intersection of the two unions is the union of the intersection of \( A \) with \( (B \cup C) \) and the set \( B \).
In summary, the simplified form of \( ( A \cup B ) \cap ( B \cup C ) \) is:
\[
( A \cap ( B \cup C )) \cup B
\]
Quick Answer
\( ( A \cap ( B \cup C )) \cup B \)
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