Best Whittaker
05/26/2024 · Senior High School
\( \left\{\begin{array}{l}\frac{x^{2}+a}{2 x+4} \quad \text { si } x<0 \\ 10 x^{2}+x+b \quad \text { si } x \geq 0\end{array}\right. \)
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The function is piecewise defined with two cases. For \( x < 0 \), the function is \( \frac{x^{2}+a}{2x+4} \), and for \( x \geq 0 \), it is \( 10x^{2}+x+b \). To ensure continuity at \( x = 0 \), the limit from the left and the right must be equal, which gives the relationship \( \frac{a}{4} = b \).
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