Frazier Phillips
02/02/2024 · Elementary School
Let \( l \) be the length of a diagonal of a rectangle whose sides have lengths \( x \) and \( y \), and assume that \( x \) and \( y \) vary with time. If \( x \) increases at a constant rate of \( \frac{1}{4} \mathrm{ft} / \mathrm{s} \) and \( y \) decreases at a constant rate of \( \frac{1}{8} \) \( \mathrm{ft} / \mathrm{s} \), how fast is the size of the diagonal changing when \( x=1 \mathrm{ft} \). and \( y=4 \mathrm{ft} \) ? Answer:
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The rate of change of the diagonal is \(-\frac{1}{4\sqrt{17}}\) ft/s when \( x = 1 \text{ ft} \) and \( y = 4 \text{ ft} \).
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