Simpson Chandler
01/04/2024 · Primary School
b. Father leaves at 7:40 a.m. to drive 20 miles to work. If his average speed is 48 mph , when will he arrive at work? \( d=\quad v \quad t \) \( d \)
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Step-by-step Solution
To find out when the father will arrive at work, we can use the formula for distance:
\[
d = v \cdot t
\]
Where:
- \( d \) is the distance (20 miles),
- \( v \) is the speed (48 mph),
- \( t \) is the time in hours.
First, we need to solve for \( t \):
\[
t = \frac{d}{v}
\]
Substituting the values:
\[
t = \frac{20 \text{ miles}}{48 \text{ mph}} \approx 0.4167 \text{ hours}
\]
To convert hours into minutes, we multiply by 60:
\[
t \approx 0.4167 \times 60 \approx 25 \text{ minutes}
\]
Now, if the father leaves at 7:40 a.m. and it takes him approximately 25 minutes to reach work, we can calculate his arrival time:
\[
7:40 \text{ a.m.} + 25 \text{ minutes} = 8:05 \text{ a.m.}
\]
Therefore, the father will arrive at work at approximately **8:05 a.m.**
Quick Answer
The father will arrive at work at approximately 8:05 a.m.
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