Daniel Byrd
04/02/2023 · High School

\( \left\{ \begin{array} { l } { 2 x - 3 } \\ { 4 x + 5 } \end{array} \right. \)

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To solve the system of equations: \[ \begin{align*} 2x - 3 &= 0 \\ 4x + 5 &= 0 \end{align*} \] We can solve each equation separately. For the first equation: \[ 2x - 3 = 0 \] Add 3 to both sides: \[ 2x = 3 \] Divide both sides by 2: \[ x = \frac{3}{2} \] For the second equation: \[ 4x + 5 = 0 \] Subtract 5 from both sides: \[ 4x = -5 \] Divide both sides by 4: \[ x = -\frac{5}{4} \] So, the solutions to the system of equations are: \[ x = \frac{3}{2} \quad \text{and} \quad x = -\frac{5}{4} \] However, since the two equations are not the same, they do not have a single solution that satisfies both equations simultaneously. Instead, they represent two different lines on a graph, and there is no point where they intersect. Therefore, the system has no solution.

Quick Answer

The system of equations has no solution.
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