Kelly Wade
03/09/2024 · High School

\( \begin{array}{ll}\text { Oblener el m.c.m de } & \text { 1) } 2,4,7= \\ \text { i) } 5,10,15= & \text { 12) }, 2,3= \\ \text { 2) } 4,6,8= & \text { 13) } 8,36,44= \\ \text { 3) } 7,19,21= & \text { 14) } 30,60,90= \\ \text { 4) } 6,12,32= & \text { 15) } 5,15,45= \\ \text { 5) } 9,21,27= & \text { 16) } 7,42,63= \\ \text { 5) } 29,36,48= & \text { 171, }, 6,9= \\ \text { 7) } 15,25,30= & \text { 18) } 20,30,40= \\ \text { 8) } 12,18,48= & \text { 19) } 25,50,150= \\ \text { 9) } 16,24,42= & \text { 20) } 39,26,52= \\ \text { 16) } 9,12,56= & \end{array} \)

UpStudy ThothAI Solution

Tutor-Verified Answer

Step-by-step Solution

Para calcular el mínimo común múltiplo (m.c.m.) de los conjuntos de números que has proporcionado, utilizaremos el método de descomposición en factores primos. A continuación, se presentan los cálculos para cada conjunto: 1) **m.c.m(2, 4, 7)**: - 2 = \(2^1\) - 4 = \(2^2\) - 7 = \(7^1\) - m.c.m = \(2^2 \cdot 7^1 = 28\) 2) **m.c.m(4, 6, 8)**: - 4 = \(2^2\) - 6 = \(2^1 \cdot 3^1\) - 8 = \(2^3\) - m.c.m = \(2^3 \cdot 3^1 = 24\) 3) **m.c.m(7, 19, 21)**: - 7 = \(7^1\) - 19 = \(19^1\) - 21 = \(3^1 \cdot 7^1\) - m.c.m = \(3^1 \cdot 7^1 \cdot 19^1 = 399\) 4) **m.c.m(6, 12, 32)**: - 6 = \(2^1 \cdot 3^1\) - 12 = \(2^2 \cdot 3^1\) - 32 = \(2^5\) - m.c.m = \(2^5 \cdot 3^1 = 96\) 5) **m.c.m(9, 21, 27)**: - 9 = \(3^2\) - 21 = \(3^1 \cdot 7^1\) - 27 = \(3^3\) - m.c.m = \(3^3 \cdot 7^1 = 189\) 6) **m.c.m(29, 36, 48)**: - 29 = \(29^1\) - 36 = \(2^2 \cdot 3^2\) - 48 = \(2^4 \cdot 3^1\) - m.c.m = \(2^4 \cdot 3^2 \cdot 29^1 = 3480\) 7) **m.c.m(15, 25, 30)**: - 15 = \(3^1 \cdot 5^1\) - 25 = \(5^2\) - 30 = \(2^1 \cdot 3^1 \cdot 5^1\) - m.c.m = \(2^1 \cdot 3^1 \cdot 5^2 = 150\) 8) **m.c.m(12, 18, 48)**: - 12 = \(2^2 \cdot 3^1\) - 18 = \(2^1 \cdot 3^2\) - 48 = \(2^4 \cdot 3^1\) - m.c.m = \(2^4 \cdot 3^2 = 144\) 9) **m.c.m(16, 24, 42)**: - 16 = \(2^4\) - 24 = \(2^3 \cdot 3^1\) - 42 = \(2^1 \cdot 3^1 \cdot 7^1\) - m.c.m = \(2^4 \cdot 3^1 \cdot 7^1 = 336\) 10) **m.c.m(39, 26, 52)**: - 39 = \(3^1 \cdot 13^1\) - 26 = \(2^1 \cdot 13^1\) - 52 = \(2^2 \cdot 13^1\) - m.c.m = \(2^2 \cdot 3^1 \cdot 13^1 = 156\) 11) **m.c.m(9, 12, 56)**: - 9 = \(3^2\) - 12 = \(2^2 \cdot 3^1\) - 56 = \(2^3 \cdot 7^1\) - m.c.m = \(2^3

Quick Answer

1) m.c.m(2, 4, 7) = 28 2) m.c.m(4, 6, 8) = 24 3) m.c.m(7, 19, 21) = 399 4) m.c.m(6, 12, 32) = 96 5) m.c.m(9, 21, 27) = 189 6) m.c.m(29, 36, 48) = 3480 7) m.c.m(15, 25, 30) = 150 8) m.c.m(12, 18, 48) = 144 9) m.c.m(16, 24, 42) = 336 10) m.c.m(39, 26, 52) = 156 11) m.c.m(9, 12, 56) = 504
Answered by UpStudy AI and reviewed by a Professional Tutor
UpStudy ThothAI
Self-Developed and Ever-Improving
Thoth AI product is constantly being upgraded and optimized.
Covers All Major Subjects
Capable of handling homework in math, chemistry, biology, physics, and more.
Instant and Accurate
Provides immediate and precise solutions and guidance.
Try Now
Ask Tutors
Ask AI
10x
Fastest way to Get Answers & Solutions
By text

Enter your question here…

By image
Re-Upload
Uploaded Files
xxxx.png0%
Submit
📸 STUDY CAN BE A REAL STRUGGLE
Why Not UpStudy It?
Select your plan below
Premium

You can enjoy

  • Step-by-step explanations
  • 24/7 expert live tutors
  • Unlimited number of questions
  • No interruptions
  • Full access to answer and
    solution
Basic
  • Limited Solutions