A quadratic function $$ f $$ is given. $$ f(x)=x^{2}+4 x-1 $$ (a) Express $$ f $$ in standard form. $$ f(x)=\square $$

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$$ f(x) = x^{2} + 4x - 1 $$ It seems there was an error in converting the expression to standard form. Let's correct it by expressing the quadratic function $$ f(x) = x^{2} + 4x - 1 $$ in standard form. The standard form of a quadratic function is $$ f(x) = ax^{2} + bx + c $$, where $$ a $$, $$ b $$, and $$ c $$ are constants. Given $$ f(x) = x^{2} + 4x - 1 $$, we can rewrite it in standard form as $$ f(x) = x^{2} + 4x - 1 $$. Therefore, the quadratic function $$ f $$ in standard form is $$ f(x) = x^{2} + 4x - 1 $$.

A quadratic function \( f \) is given. \( f(x)=x^{2}+4 x-1 \) (a) Express \( f \) in standard form. \( f(x)=\square \)

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A quadratic function \( f \) is given. \( f(x)=x^{2}+4 x-1 \) (a) Express \( f \) in standard form. \( f(x)=\square \)

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