Malone Lowe
11/15/2023 · High School
a: \( \frac{\left.\left(\frac{3}{4}\right)^{-3}\left(\frac{3}{4}\right)^{6}\left(\frac{3}{4}\right)^{9}+\frac{256}{81}\right)^{-2}}{\left(\frac{4}{3}\right)^{-5}\left(\frac{3}{4}\right)^{1}\left[\left(\frac{3}{4}\right)^{5}\right]^{2}\left(\frac{27}{64}\right)^{3}}= \)
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Tutor-Verified Answer
Step-by-step Solution
To simplify the expression
\[
a = \frac{\left.\left(\frac{3}{4}\right)^{-3}\left(\frac{3}{4}\right)^{6}\left(\frac{3}{4}\right)^{9}+\frac{256}{81}\right)^{-2}}{\left(\frac{4}{3}\right)^{-5}\left(\frac{3}{4}\right)^{1}\left[\left(\frac{3}{4}\right)^{5}\right]^{2}\left(\frac{27}{64}\right)^{3}}
\]
we will simplify both the numerator and the denominator step by step.
### Step 1: Simplify the Numerator
The numerator is
\[
\left(\frac{3}{4}\right)^{-3}\left(\frac{3}{4}\right)^{6}\left(\frac{3}{4}\right)^{9} + \frac{256}{81}
\]
Using the property of exponents, we can combine the terms:
\[
\left(\frac{3}{4}\right)^{-3 + 6 + 9} = \left(\frac{3}{4}\right)^{12}
\]
Thus, the numerator becomes:
\[
\left(\frac{3}{4}\right)^{12} + \frac{256}{81}
\]
Next, we need to express \(\frac{256}{81}\) in terms of \(\left(\frac{3}{4}\right)^{12}\). We can rewrite \(\frac{256}{81}\) as:
\[
\frac{256}{81} = \frac{4^4}{3^4} = \left(\frac{4}{3}\right)^{4}
\]
Now we have:
\[
\left(\frac{3}{4}\right)^{12} + \left(\frac{4}{3}\right)^{4}
\]
To combine these, we can express \(\left(\frac{4}{3}\right)^{4}\) in terms of \(\left(\frac{3}{4}\right)^{12}\):
\[
\left(\frac{4}{3}\right)^{4} = \left(\frac{3}{4}\right)^{-4}
\]
Thus, the numerator becomes:
\[
\left(\frac{3}{4}\right)^{12} + \left(\frac{3}{4}\right)^{-4}
\]
### Step 2: Simplify the Denominator
The denominator is
\[
\left(\frac{4}{3}\right)^{-5}\left(\frac{3}{4}\right)^{1}\left[\left(\frac{3}{4}\right)^{5}\right]^{2}\left(\frac{27}{64}\right)^{3}
\]
First, simplify \(\left[\left(\frac{3}{4}\right)^{5}\right]^{2}\):
\[
\left(\frac{3}{4}\right)^{10}
\]
Now, the denominator becomes:
\[
\left(\frac{4}{3}\right)^{-5} \left(\frac{3}{4}\right)^{1} \left(\frac{3}{4}\right)^{10} \left(\frac{27}{64}\right)^{3}
\]
Combining the powers of \(\left(\frac{3}{4}\right)\):
\[
\left(\frac{4}{3}\right)^{-5} \left(\frac{3}{4}\right)^{11} \left(\frac{27}{64}\right)^{3}
\]
Next, simplify \(\left(\frac{27}{64}\right)^{3}\):
\[
\left(\frac{27}{64}\right)^{3} = \frac{27^3}{64^3} = \frac{19683}{262144}
\]
Now, we can express \(\left(\frac{4}{3}\right)^{-5}\) as:
\[
\left(\frac{3}{4}\right)^{5}
\]
Thus, the denominator becomes:
\[
\left(\frac{3}{4}\right)^{5} \left(\frac{3}{4}\right)^{11} \cdot \frac{19683}{262144} = \left(\frac{3}{4}\right)^{16} \cdot \frac{19683}{262144}
\]
### Step 3: Combine the Results
Now we can rewrite \(a\):
\[
a = \frac{\left(\left(\frac{3}{4}\right)^{12} + \
Quick Answer
a = \frac{\left(\left(\frac{3}{4}\right)^{12} + \left(\frac{3}{4}\right)^{-4}\right)^{-2}}{\left(\frac{3}{4}\right)^{16} \cdot \frac{19683}{262144}}
\]
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