1.8 Explain the meaning of parity of authority and responsibility ( 2 poin 1.9 Describe the scalar principle? ( 2 points)

O resto da divisão de \( 3 x-8 x^{2}+a x-4 \) por \( 3 x-2 \) seja -2

\begin{tabular}{l} 3. O preço da gasolina nas refinarias é de \( \mathrm{R} \$ 2,08 / \) litro, o que significa um reajuste de \( +4,0 \% \) em relação \\ aos valores anteriores. Na bomba, essa gasolina, após a inserção de todos os impostos e olucro do posto, \\ passa a custar \( \mathrm{R} \$ 5,72 / l i t r o \). \\ a. Qual era o preço da gasolina nas refinarias antes do aumento? \\ \hline\end{tabular}

1. Resuelva y simplifique (si es el caso) las siguientes operaciones con fracciones \( \begin{array}{ll}\text { A. } \frac{2}{5}+1 & \text { O. } \frac{a}{2}+\frac{b}{2}+\frac{c}{2} \\ \text { B. } \frac{2}{7}+\frac{1}{5} & \text { P. } \frac{2}{a}+\frac{2}{b}+\frac{2}{c} \\ \text { C. } \frac{2}{5}+3 & \text { Q. } \frac{c}{a}+\frac{b}{b}+\frac{a}{c} \\ \text { D. } \frac{30}{15}+\frac{125}{5}+\frac{1}{2} & \text { R. } \frac{1}{6}+(a-1)^{2} \\ \text { E. } \frac{32}{3}+3 \times 322 & \text { S. } \frac{1}{2}+\frac{(a-1)}{2}+\frac{1}{6} \\ \text { F. } \frac{165}{6}+1+\frac{1}{200} & \text { T. } \frac{a}{a}+\frac{a^{2}}{a}+\frac{a^{3}}{a}+\frac{a^{4}}{a}+\frac{a^{3}}{a} \\ \text { G. } \frac{1}{3}+\frac{1}{2}+\frac{1}{3}+\frac{1}{2}+\frac{1}{3}+\frac{1}{2} & \text { U. } \frac{2 x}{a}+\frac{7 x a}{a y}+\frac{36 a}{b c d} \\ \text { H. } \frac{1}{2}+\frac{2}{1}+\frac{1}{2}+\frac{2}{1}+\frac{1}{2} & \text { V. } \frac{2 x y z w}{a}+\frac{2 a b c d}{x} \\ \text { I. } 1+\frac{1}{2}+\frac{1}{2}+\frac{1}{2}+\frac{1}{2} & \text { W. } \frac{a b c d e f}{u v w x y z}+\frac{u v w x y z}{a b c d e f}+1 \\ \text { J. } \frac{1}{6}+\frac{1}{6}+\frac{1}{6}+\frac{1}{6}+\frac{1}{6}+\frac{1}{6} & \text { X. } \frac{x^{2}}{2}+\frac{x^{3}}{3}+\frac{x^{5}}{5}+\frac{x^{7}}{7}+\frac{x^{11}}{11} \\ \text { K. } \frac{3}{4}+45+9 \times \frac{2}{3}+\frac{1}{2} & \text { Y. } \frac{2 x^{2}}{129}+\frac{3 x^{2}}{129}+\frac{5 x^{2}}{129}+\frac{7 x^{2}}{129}+\frac{11 x^{2}}{129}+ \\ \text { L. } 1+\frac{1}{2}+\frac{1}{4}+\frac{1}{6}+\frac{1}{8}+\frac{1}{10}+\frac{1}{12} & \frac{13 x^{2}}{129}+\frac{17 x^{2}}{129}+\frac{19 x^{2}}{129}+\frac{23 x^{2}}{129}+\frac{29 x^{2}}{129} \\ \text { M. } 1+\frac{1}{3}+\frac{1}{6}+\frac{1}{9}+\frac{1}{12}+\frac{1}{15} & \\ \text { N. } \frac{a}{6}+a & \end{array} \)

\( \left. \begin{array} { l } { a + ( b \cdot c ) ^ { 2 } - 2 a b ; \quad a = 3 , b = 2 , c = 4 } \\ { 3 a b - 2 a ^ { 2 } : ( b + 1 ) ; \quad a = 2 , b = 3 } \end{array} \right. \)

Solve for \( v \). \[ 6 v+8=8 v \] Simplify your answer as much as possible. \( v=\square \)