Consider the graph of the function \( f(x)=\frac{x^{2}-16}{x^{3}-5 x^{2}+4 x} \). What are the vertical asymptotes? Just list the \( x \)-values, separated by commas. Provide your answer below: \[ x=\square \]

Find the vertical asymptotes of \( (x^2-16)/(x^3-5x^2+4x) \). Function by following steps: - step0: Find the vertical asymptotes: \(y=\frac{x^{2}-16}{x^{3}-5x^{2}+4x}\) - step1: Evaluate the limit: \(\begin{align}&\lim _{x\rightarrow 0}\left(\frac{x^{2}-16}{x^{3}-5x^{2}+4x}\right)\\&\lim _{x\rightarrow 1}\left(\frac{x^{2}-16}{x^{3}-5x^{2}+4x}\right)\\&\lim _{x\rightarrow 4}\left(\frac{x^{2}-16}{x^{3}-5x^{2}+4x}\right)\end{align}\) - step2: Calculate: \(\begin{align}&\textrm{The limit does not exist}\\&\textrm{The limit does not exist}\\&\frac{2}{3}\end{align}\) - step3: \(x=0\) is a vertical asymptote\(:\) \(\begin{align}&x=0\textrm{ }\textrm{is a vertical asymptote}\\&x=1\textrm{ }\textrm{is a vertical asymptote}\\&x=4\textrm{ }\textrm{is not a vertical asymptote}\end{align}\) - step4: List all vertical asymptotes of the function: \(\begin{align}&x=0\\&x=1\end{align}\) The vertical asymptotes of the function \( f(x)=\frac{x^{2}-16}{x^{3}-5 x^{2}+4 x} \) are at \( x=0 \) and \( x=1 \). Therefore, the \( x \)-values of the vertical asymptotes are \( 0, 1 \).