Robbins Fernandez
07/05/2023 · Elementary School
11) Discussion Topic: 1. A mass-spring system has a mass \( (\mathrm{m}) \) of 0.5 kg and a stiffness \( (\mathrm{k}) \) of \( 100 \mathrm{~N} / \mathrm{m} \). Calculate
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To calculate the properties of a mass-spring system, we can use the following formulas:
1. Natural Frequency (\( \omega_n \)):
\[ \omega_n = \sqrt{\frac{k}{m}} \]
2. Period (\( T \)):
\[ T = \frac{2\pi}{\omega_n} \]
3. Frequency (\( f \)):
\[ f = \frac{1}{T} \]
Given:
- Mass (\( m \)): 0.5 kg
- Stiffness (\( k \)): 100 N/m
Let's calculate the natural frequency (\( \omega_n \)), period (\( T \)), and frequency (\( f \)) of the mass-spring system.
Calculate the value by following steps:
- step0: Calculate:
\(\sqrt{\frac{100}{0.5}}\)
- step1: Divide the numbers:
\(\sqrt{200}\)
- step2: Write as a product:
\(\sqrt{100\times 2}\)
- step3: Write in exponential form:
\(\sqrt{10^{2}\times 2}\)
- step4: Use the properties of radicals:
\(\sqrt{10^{2}}\times \sqrt{2}\)
- step5: Simplify the root:
\(10\sqrt{2}\)
The natural frequency (\( \omega_n \)) of the mass-spring system is approximately \( 14.142136 \, \text{rad/s} \).
Next, let's calculate the period (\( T \)) of the mass-spring system.
Calculate the value by following steps:
- step0: Calculate:
\(\frac{2\pi }{14.142136}\)
- step1: Convert the expressions:
\(\frac{2\pi }{\frac{1767767}{125000}}\)
- step2: Multiply by the reciprocal:
\(2\pi \times \frac{125000}{1767767}\)
- step3: Multiply:
\(\frac{2\pi \times 125000}{1767767}\)
- step4: Multiply:
\(\frac{250000\pi }{1767767}\)
The period (\( T \)) of the mass-spring system is approximately 0.444288 seconds.
Finally, let's calculate the frequency (\( f \)) of the mass-spring system.
Calculate the value by following steps:
- step0: Calculate:
\(\frac{1}{0.444288}\)
- step1: Convert the expressions:
\(\frac{1}{\frac{6942}{15625}}\)
- step2: Multiply by the reciprocal:
\(\frac{15625}{6942}\)
The frequency (\( f \)) of the mass-spring system is approximately 2.250792 Hz.
Therefore, the properties of the mass-spring system are:
- Natural Frequency (\( \omega_n \)): \( 14.142136 \, \text{rad/s} \)
- Period (\( T \)): \( 0.444288 \, \text{s} \)
- Frequency (\( f \)): \( 2.250792 \, \text{Hz} \)
Quick Answer
The natural frequency is approximately \( 14.142136 \, \text{rad/s} \), the period is approximately \( 0.444288 \, \text{s} \), and the frequency is approximately \( 2.250792 \, \text{Hz} \).
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