Warner Hills
08/17/2024 · Senior High School
Déduire que \( \overrightarrow{C^{\prime} D^{\prime}}=\overrightarrow{A^{\prime} \vec{E}^{\prime}} \)
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Pour montrer que \( \overrightarrow{C^{\prime} D^{\prime}}=\overrightarrow{A^{\prime} \vec{E}^{\prime}} \), il faut vérifier que le déplacement de \( C^{\prime} \) vers \( D^{\prime} \) est identique au déplacement de \( A^{\prime} \) vers \( \vec{E}^{\prime} \).
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