Daniels Little
02/08/2023 · Middle School
iclo iv 1) \( x^{3}-2 x^{4}+5 x-7+\left(5 x^{3}+x\right) \) \( \left.-9 x^{2}+6 x-3\right) \) 3) \( \left(4 x^{2}+3 x+5+\left(-9 x^{4}+5 x^{2}+6 x^{2}-2 x+7\right)+\left(-4 x^{2}+\right.\right. \) 1) \( \left(10-2 x^{2}-3 x\right)+\left(4 x^{2}+5-3 x\right) \) \( 5 x^{2}+2 x+3 \) Por \( 5 x^{3} \) 1) \( 15 x^{3}-12 x^{2}+6 \div 3 x \).
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Tutor-Verified Answer
Step-by-step Solution
为了解决这些代数问题,我们需要对每个表达式进行化简。下面是每个问题的详细解答步骤:
### 问题 1
表达式为:
\[ x^{3} - 2x^{4} + 5x - 7 + (5x^{3} + x) - (9x^{2} - 6x - 3) \]
**步骤 1:去掉括号**
\[ x^{3} - 2x^{4} + 5x - 7 + 5x^{3} + x - 9x^{2} + 6x + 3 \]
**步骤 2:合并同类项**
\[ -2x^{4} + (x^{3} + 5x^{3}) - 9x^{2} + (5x + x + 6x) + (-7 + 3) \]
\[ -2x^{4} + 6x^{3} - 9x^{2} + 12x - 4 \]
所以,化简后的表达式为:
\[ -2x^{4} + 6x^{3} - 9x^{2} + 12x - 4 \]
### 问题 2
表达式为:
\[ (10 - 2x^{2} - 3x) + (4x^{2} + 5 - 3x) \]
**步骤 1:去掉括号**
\[ 10 - 2x^{2} - 3x + 4x^{2} + 5 - 3x \]
**步骤 2:合并同类项**
\[ (-2x^{2} + 4x^{2}) + (-3x - 3x) + (10 + 5) \]
\[ 2x^{2} - 6x + 15 \]
所以,化简后的表达式为:
\[ 2x^{2} - 6x + 15 \]
### 问题 3
表达式为:
\[ (4x^{2} + 3x + 5 + (-9x^{4} + 5x^{2} + 6x^{2} - 2x + 7) + (-4x^{2} + 1)) \]
**步骤 1:去掉括号**
\[ 4x^{2} + 3x + 5 - 9x^{4} + 5x^{2} + 6x^{2} - 2x + 7 - 4x^{2} + 1 \]
**步骤 2:合并同类项**
\[ -9x^{4} + (4x^{2} + 5x^{2} + 6x^{2} - 4x^{2}) + (3x - 2x) + (5 + 7 + 1) \]
\[ -9x^{4} + 7x^{2} + x + 13 \]
所以,化简后的表达式为:
\[ -9x^{4} + 7x^{2} + x + 13 \]
### 问题 4
表达式为:
\[ 15x^{3} - 12x^{2} + 6 \div 3x \]
**步骤 1:先进行除法**
\[ 15x^{3} - 12x^{2} + \frac{6}{3x} \]
\[ 15x^{3} - 12x^{2} + 2x^{-1} \]
所以,化简后的表达式为:
\[ 15x^{3} - 12x^{2} + 2x^{-1} \]
通过以上步骤,我们得到了每个问题的化简结果。
Quick Answer
1) \(-2x^{4} + 6x^{3} - 9x^{2} + 12x - 4\)
2) \(2x^{2} - 6x + 15\)
3) \(-9x^{4} + 7x^{2} + x + 13\)
4) \(15x^{3} - 12x^{2} + 2x^{-1}\)
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