Daniels Little
02/08/2023 · Middle School

iclo iv 1) \( x^{3}-2 x^{4}+5 x-7+\left(5 x^{3}+x\right) \) \( \left.-9 x^{2}+6 x-3\right) \) 3) \( \left(4 x^{2}+3 x+5+\left(-9 x^{4}+5 x^{2}+6 x^{2}-2 x+7\right)+\left(-4 x^{2}+\right.\right. \) 1) \( \left(10-2 x^{2}-3 x\right)+\left(4 x^{2}+5-3 x\right) \) \( 5 x^{2}+2 x+3 \) Por \( 5 x^{3} \) 1) \( 15 x^{3}-12 x^{2}+6 \div 3 x \).

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Step-by-step Solution

为了解决这些代数问题,我们需要对每个表达式进行化简。下面是每个问题的详细解答步骤: ### 问题 1 表达式为: \[ x^{3} - 2x^{4} + 5x - 7 + (5x^{3} + x) - (9x^{2} - 6x - 3) \] **步骤 1:去掉括号** \[ x^{3} - 2x^{4} + 5x - 7 + 5x^{3} + x - 9x^{2} + 6x + 3 \] **步骤 2:合并同类项** \[ -2x^{4} + (x^{3} + 5x^{3}) - 9x^{2} + (5x + x + 6x) + (-7 + 3) \] \[ -2x^{4} + 6x^{3} - 9x^{2} + 12x - 4 \] 所以,化简后的表达式为: \[ -2x^{4} + 6x^{3} - 9x^{2} + 12x - 4 \] ### 问题 2 表达式为: \[ (10 - 2x^{2} - 3x) + (4x^{2} + 5 - 3x) \] **步骤 1:去掉括号** \[ 10 - 2x^{2} - 3x + 4x^{2} + 5 - 3x \] **步骤 2:合并同类项** \[ (-2x^{2} + 4x^{2}) + (-3x - 3x) + (10 + 5) \] \[ 2x^{2} - 6x + 15 \] 所以,化简后的表达式为: \[ 2x^{2} - 6x + 15 \] ### 问题 3 表达式为: \[ (4x^{2} + 3x + 5 + (-9x^{4} + 5x^{2} + 6x^{2} - 2x + 7) + (-4x^{2} + 1)) \] **步骤 1:去掉括号** \[ 4x^{2} + 3x + 5 - 9x^{4} + 5x^{2} + 6x^{2} - 2x + 7 - 4x^{2} + 1 \] **步骤 2:合并同类项** \[ -9x^{4} + (4x^{2} + 5x^{2} + 6x^{2} - 4x^{2}) + (3x - 2x) + (5 + 7 + 1) \] \[ -9x^{4} + 7x^{2} + x + 13 \] 所以,化简后的表达式为: \[ -9x^{4} + 7x^{2} + x + 13 \] ### 问题 4 表达式为: \[ 15x^{3} - 12x^{2} + 6 \div 3x \] **步骤 1:先进行除法** \[ 15x^{3} - 12x^{2} + \frac{6}{3x} \] \[ 15x^{3} - 12x^{2} + 2x^{-1} \] 所以,化简后的表达式为: \[ 15x^{3} - 12x^{2} + 2x^{-1} \] 通过以上步骤,我们得到了每个问题的化简结果。

Quick Answer

1) \(-2x^{4} + 6x^{3} - 9x^{2} + 12x - 4\) 2) \(2x^{2} - 6x + 15\) 3) \(-9x^{4} + 7x^{2} + x + 13\) 4) \(15x^{3} - 12x^{2} + 2x^{-1}\)
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