Reyes Gray
08/17/2024 · Senior High School
Data la funzione \[ f(x)=\left\{\begin{array}{ll}3 x^{2}+a & \text { se } x<0 \\ \frac{2 x+1}{x-b} & \text { se } x \geq 0\end{array}\right. \] trova per quali valori di \( a \) e \( b \) la funzione è continua in \( x=0 \) e ha un asintoto verticale di equazione \( x=1 \) Rappresenta il grafico di \( f(x) \).
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Per la continuità in \( x=0 \) e l'asintoto verticale in \( x=1 \), i valori di \( a \) e \( b \) sono \( a = -1 \) e \( b = 1 \).
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