a. \( x=1>8 \) b. \( 3 x-8 \leq x+6 \)

Let's solve the inequalities step by step. ### a. \( x = 1 > 8 \) This statement is not true. The value of \( x \) is 1, which is not greater than 8. Therefore, this inequality does not hold. ### b. \( 3x - 8 \leq x + 6 \) To solve this inequality, we will isolate \( x \). 1. Start with the original inequality: \[ 3x - 8 \leq x + 6 \] 2. Subtract \( x \) from both sides: \[ 3x - x - 8 \leq 6 \] This simplifies to: \[ 2x - 8 \leq 6 \] 3. Next, add 8 to both sides: \[ 2x \leq 6 + 8 \] This simplifies to: \[ 2x \leq 14 \] 4. Finally, divide both sides by 2: \[ x \leq 7 \] ### Summary of Results - For part (a), the statement \( x = 1 > 8 \) is false. - For part (b), the solution is \( x \leq 7 \).