Mullins Barrett
03/10/2023 · High School
\( \begin{array}{ll}\text { (a) } \frac{x+2}{x-2}+\frac{x}{x+2}=\frac{1}{2} & \text { b) } \\ \text { 5. Të zgjidhen ekuacionet kuadratike sipas } x \text {-it ( } a \text { parame } \\ \text { a) }(x+a)(x-a)-2 a x=a(3 a-2 x) \text {; }\end{array} \)
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The equation \( \frac{x+2}{x-2}+\frac{x}{x+2}=\frac{1}{2} \) has no real solution. The quadratic equation \( (x+a)(x-a)-2ax=a(3a-2x) \) has solutions \( x=2a \) and \( x=-2a \).
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