(3) \( f(x)=3-2 x, \quad M(7 ; 5) \);

It seems like you're providing a function \( f(x) = 3 - 2x \) and a point \( M(7, 5) \). However, it's not clear what you would like to do with this information. Here are a few possibilities: 1. **Evaluate the function at \( x = 7 \)**: \[ f(7) = 3 - 2(7) = 3 - 14 = -11 \] 2. **Check if the point \( M(7, 5) \) lies on the graph of the function**: The point \( M(7, 5) \) lies on the graph of \( f(x) \) if \( f(7) = 5 \). From the previous calculation, we found that \( f(7) = -11 \), so the point \( M(7, 5) \) does not lie on the graph of the function. 3. **Find the slope of the line represented by the function**: The function \( f(x) = 3 - 2x \) is in slope-intercept form \( y = mx + b \), where \( m \) is the slope. Here, the slope \( m = -2 \). 4. **Find the y-intercept**: The y-intercept occurs when \( x = 0 \): \[ f(0) = 3 - 2(0) = 3 \] So the y-intercept is \( (0, 3) \). If you have a specific question or task in mind regarding the function or the point, please let me know!