Hobbs Cross
03/03/2024 · Middle School
14. \( \lim _{\Delta \rightarrow} \frac{(x+\Delta x)^{2}-x^{2}}{\Delta x} \)
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Tutor-Verified Answer
Step-by-step Solution
To evaluate the limit
\[
\lim_{\Delta x \to 0} \frac{(x+\Delta x)^{2} - x^{2}}{\Delta x},
\]
we start by simplifying the expression in the numerator. We can expand \((x + \Delta x)^2\):
\[
(x + \Delta x)^2 = x^2 + 2x\Delta x + (\Delta x)^2.
\]
Now, substituting this back into the limit gives us:
\[
\lim_{\Delta x \to 0} \frac{(x^2 + 2x\Delta x + (\Delta x)^2) - x^2}{\Delta x}.
\]
The \(x^2\) terms cancel out:
\[
\lim_{\Delta x \to 0} \frac{2x\Delta x + (\Delta x)^2}{\Delta x}.
\]
Next, we can factor out \(\Delta x\) from the numerator:
\[
\lim_{\Delta x \to 0} \frac{\Delta x(2x + \Delta x)}{\Delta x}.
\]
Assuming \(\Delta x \neq 0\), we can cancel \(\Delta x\):
\[
\lim_{\Delta x \to 0} (2x + \Delta x).
\]
Now, we can directly substitute \(\Delta x = 0\):
\[
2x + 0 = 2x.
\]
Thus, the limit evaluates to:
\[
\boxed{2x}.
\]
Quick Answer
The limit is \(2x\).
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