1. The children wanted to decorate around the edge of the blackboard in the classroom The length of the board is 2450 mm and the width is 1160 mm . How much ribbon will they need? 2. Farmer Mkhize needs to replace the fence around his pasture. He measures the pasture and records the following measurements: \( 472 \mathrm{~m}, 585 \mathrm{~m}, 390 \mathrm{~m}, 648 \mathrm{~m} \) and 524 m . a. How much fencing must he buy to complete the job? b. If the fencing costs R100 per metre, how much will it cost him?

To solve both problems, we need to calculate the perimeter for each scenario. ### 1. Ribbon for the Blackboard The formula for the perimeter \( P \) of a rectangle is given by: \[ P = 2 \times (\text{length} + \text{width}) \] Given: - Length = 2450 mm - Width = 1160 mm Now, substituting the values into the formula: \[ P = 2 \times (2450 \, \text{mm} + 1160 \, \text{mm}) \] \[ P = 2 \times (3610 \, \text{mm}) \] \[ P = 7220 \, \text{mm} \] So, the children will need **7220 mm** of ribbon. ### 2. Fencing for Farmer Mkhize a. To find the total length of fencing needed, we simply add up all the measurements of the pasture: \[ \text{Total length} = 472 \, \text{m} + 585 \, \text{m} + 390 \, \text{m} + 648 \, \text{m} + 524 \, \text{m} \] Calculating this: \[ \text{Total length} = 472 + 585 + 390 + 648 + 524 = 2619 \, \text{m} \] So, Farmer Mkhize must buy **2619 m** of fencing. b. To find the total cost of the fencing, we multiply the total length by the cost per meter: \[ \text{Cost} = \text{Total length} \times \text{Cost per meter} \] \[ \text{Cost} = 2619 \, \text{m} \times R100/\text{m} \] \[ \text{Cost} = R261900 \] Thus, the total cost for the fencing will be **R261900**.