Reed Harper
08/14/2024 · Middle School
a) \( 133=13 \cdot++ \) b) \( 297=12 \cdot++ \) c) \( 19=33 \cdot++ \) d) \( 176=+15+11 \)
UpStudy ThothAI Solution
Tutor-Verified Answer
Step-by-step Solution
It looks like you're presenting equations that involve some unknowns represented by "++" and "+" symbols. Let's solve each equation step by step.
a) \( 133 = 13 \cdot ++ \)
To find the value of "++", we can rearrange the equation:
\[
++ = \frac{133}{13} = 10.230769 \ldots
\]
So, "++" is approximately \( 10.23 \).
b) \( 297 = 12 \cdot ++ \)
Similarly, we can solve for "++":
\[
++ = \frac{297}{12} = 24.75
\]
So, "++" is \( 24.75 \).
c) \( 19 = 33 \cdot ++ \)
Now, we solve for "++":
\[
++ = \frac{19}{33} \approx 0.575757 \ldots
\]
So, "++" is approximately \( 0.576 \).
d) \( 176 = +15 + 11 \)
This equation seems to be a bit different since it involves addition. Let's solve for "+".
First, we can combine the constants:
\[
+15 + 11 = 26
\]
Now, we can rearrange the equation:
\[
176 = +26
\]
This means that "+" must be equal to \( 176 - 26 = 150 \).
So, the values are:
a) \( ++ \approx 10.23 \)
b) \( ++ = 24.75 \)
c) \( ++ \approx 0.576 \)
d) \( + = 150 \)
Quick Answer
a) \( ++ \approx 10.23 \)
b) \( ++ = 24.75 \)
c) \( ++ \approx 0.576 \)
d) \( + = 150 \)
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