Harrington Coleman
10/21/2023 · Middle School
1. Show that : \( (\sqrt{3}+\sqrt{2}) 3+(\sqrt{3}-\sqrt{2}) 3=18 \sqrt{3} \)
UpStudy ThothAI Solution
Tutor-Verified Answer
Step-by-step Solution
To show that
\[
(\sqrt{3}+\sqrt{2}) 3 + (\sqrt{3}-\sqrt{2}) 3 = 18 \sqrt{3},
\]
we can start by simplifying the left-hand side.
First, we can factor out the common term \(3\):
\[
3 \left( (\sqrt{3}+\sqrt{2}) + (\sqrt{3}-\sqrt{2}) \right).
\]
Next, we simplify the expression inside the parentheses:
\[
(\sqrt{3}+\sqrt{2}) + (\sqrt{3}-\sqrt{2}) = \sqrt{3} + \sqrt{2} + \sqrt{3} - \sqrt{2} = 2\sqrt{3}.
\]
Now, substituting this back into our expression gives:
\[
3 \cdot 2\sqrt{3} = 6\sqrt{3}.
\]
However, we need to check if this equals \(18\sqrt{3}\). It seems there was a misunderstanding in the original equation.
Let's re-evaluate the original expression:
\[
(\sqrt{3}+\sqrt{2}) 3 + (\sqrt{3}-\sqrt{2}) 3 = 3(\sqrt{3}+\sqrt{2} + \sqrt{3}-\sqrt{2}) = 3(2\sqrt{3}) = 6\sqrt{3}.
\]
Thus, we find that:
\[
6\sqrt{3} \neq 18\sqrt{3}.
\]
Therefore, the statement
\[
(\sqrt{3}+\sqrt{2}) 3 + (\sqrt{3}-\sqrt{2}) 3 = 18 \sqrt{3}
\]
is incorrect. The correct simplification shows that the left-hand side equals \(6\sqrt{3}\).
Quick Answer
The statement is incorrect. The left-hand side simplifies to \(6\sqrt{3}\), not \(18\sqrt{3}\).
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