Translate triangle \( A B C \) by 3 units to the left and 5 units down. Which of the following are the coordinates of new triangle \( A^{\prime} B^{\prime} C^{\prime} \) ? (1 point)

To translate triangle \( ABC \) by 3 units to the left and 5 units down, you need to subtract 3 from the x-coordinates and 5 from the y-coordinates of each vertex of the triangle. If the original coordinates of the vertices are: - \( A(x_1, y_1) \) - \( B(x_2, y_2) \) - \( C(x_3, y_3) \) The new coordinates after the translation will be: - \( A'(x_1 - 3, y_1 - 5) \) - \( B'(x_2 - 3, y_2 - 5) \) - \( C'(x_3 - 3, y_3 - 5) \) If you provide the original coordinates of triangle \( ABC \), I can help you calculate the new coordinates for triangle \( A'B'C' \).