2) \( 4 a=2 b+a=b \)

To solve the equation \( 4a = 2b + a = b \), we can break it down into two separate equations: 1. \( 4a = 2b + a \) 2. \( 2b + a = b \) Let's solve these equations step by step. ### Step 1: Solve the second equation From the second equation \( 2b + a = b \), we can rearrange it: \[ 2b + a - b = 0 \implies b + a = 0 \implies b = -a \] ### Step 2: Substitute \( b \) into the first equation Now, substitute \( b = -a \) into the first equation \( 4a = 2b + a \): \[ 4a = 2(-a) + a \] This simplifies to: \[ 4a = -2a + a \] Combining like terms on the right side gives: \[ 4a = -a \] ### Step 3: Solve for \( a \) Now, add \( a \) to both sides: \[ 4a + a = 0 \implies 5a = 0 \] Thus, we find: \[ a = 0 \] ### Step 4: Find \( b \) Now that we have \( a = 0 \), we can find \( b \) using \( b = -a \): \[ b = -0 = 0 \] ### Conclusion The solution to the equations is: \[ a = 0, \quad b = 0 \]