Fowler Warren
05/23/2023 · High School
For the following alternating series, \( \sum_{n=1}^{\infty} a_{n}=1-\frac{(0.45)^{2}}{2!}+\frac{(0.45)^{4}}{4!}-\frac{(0.45)^{6}}{6!}+\frac{(0.45)^{8}}{8!}-\ldots \) how many terms do you have to go for your approximation (your partial sum) to be within 0.0000001 from the convergent value of that series?
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To be within 0.0000001 of the convergent value, you need to sum 4 terms of the series.
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