Hart Wells
07/05/2023 · Junior High School

Carla runs ever 3 days. She swims every Thursday. On Thursday 9 November, Carla both runs and swims. What will be the next date on which she both runs and swims?

UpStudy ThothAI Solution

Tutor-Verified Answer

Step-by-step Solution

To find the next date on which Carla both runs and swims, we need to determine the pattern of her activities and calculate the next occurrence. Given: - Carla runs every 3 days. - Carla swims every Thursday. Since Carla runs every 3 days, we can calculate the next date she runs by adding 3 days to the current date. Since Carla swims every Thursday, we can calculate the next date she swims by finding the next Thursday after the current date. Let's calculate the next date on which Carla both runs and swims. Calculate the value by following steps: - step0: Calculate: \(9+3\) - step1: Add the numbers: \(12\) The next date on which Carla runs is 12 November. Now, let's find the next Thursday after 9 November. Calculate the value by following steps: - step0: Calculate: \(9+7\) - step1: Add the numbers: \(16\) The next Thursday after 9 November is 16 November. Therefore, the next date on which Carla both runs and swims will be 16 November.

Quick Answer

The next date on which Carla both runs and swims will be 16 November.
Answered by UpStudy AI and reviewed by a Professional Tutor
UpStudy ThothAI
Self-Developed and Ever-Improving
Thoth AI product is constantly being upgraded and optimized.
Covers All Major Subjects
Capable of handling homework in math, chemistry, biology, physics, and more.
Instant and Accurate
Provides immediate and precise solutions and guidance.
Try Now
Ask Tutors
Ask AI
10x
Fastest way to Get Answers & Solutions
By text

Enter your question here…

By image
Re-Upload
Uploaded Files
xxxx.png0%
Submit
📸 STUDY CAN BE A REAL STRUGGLE
Why Not UpStudy It?
Select your plan below
Premium

You can enjoy

  • Step-by-step explanations
  • 24/7 expert live tutors
  • Unlimited number of questions
  • No interruptions
  • Full access to answer and
    solution
Basic
  • Limited Solutions