Lindsey Warner
12/22/2023 · Junior High School
Sin resolver analiticamente, indicar si el sistema tiene o no solución. Lue clasificarlo. Justificar. \[ \left\{\begin{array}{c}x+3 y+2 z=3 \\ x=(y+z)(-2)-y+1 \\ 2 z=-3 y-4-x\end{array}\right. \]
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El sistema de ecuaciones no tiene solución y se clasifica como inconsistente. La contradicción surge al intentar igualar las expresiones para \( x \) de las Ecuaciones 2 y 3, lo que indica que no hay valores de \( y \) y \( z \) que satisfagan todas las ecuaciones simultáneamente.
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